16t^2=555

Solution for 16t^2=555 equation:

16t^2=555

We move all terms to the left:

16t^2-(555)=0

a = 16; b = 0; c = -555;
Δ = b2-4ac
Δ = 02-4·16·(-555)
Δ = 35520
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{35520}=\sqrt{64*555}=\sqrt{64}*\sqrt{555}=8\sqrt{555}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{555}}{2*16}=\frac{0-8\sqrt{555}}{32}
=-\frac{8\sqrt{555}}{32}
=-\frac{\sqrt{555}}{4}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{555}}{2*16}=\frac{0+8\sqrt{555}}{32}
=\frac{8\sqrt{555}}{32}
=\frac{\sqrt{555}}{4}
$